《2025年一本暑假计算加应用题五年级数学北师大版》

1. 直接写出得数。(每题1★)
$\frac {1}{2}+\frac {1}{3}=$$\frac{5}{6}$ $\frac {1}{5}-\frac {1}{6}=$$\frac{1}{30}$ $\frac {5}{6}+\frac {1}{6}=$1 $\frac {1}{7}+\frac {1}{5}=$$\frac{12}{35}$
$\frac {1}{6}-\frac {1}{7}=$$\frac{1}{42}$ $\frac {1}{3}+\frac {1}{5}=$$\frac{8}{15}$ $\frac {1}{3}+2=$$2\frac{1}{3}$ $\frac {3}{16}+\frac {1}{2}=$$\frac{11}{16}$
$1-\frac {3}{8}=$$\frac{5}{8}$ $\frac {1}{5}+\frac {4}{5}=$1 $\frac {3}{10}-\frac {1}{10}=$$\frac{1}{5}$ $\frac {5}{6}+\frac {1}{2}=$$\frac{4}{3}$
$\frac {1}{4}-\frac {1}{5}=$$\frac{1}{20}$ $\frac {3}{4}-\frac {1}{2}=$$\frac{1}{4}$ $\frac {5}{9}+\frac {1}{3}=$$\frac{8}{9}$ $\frac {1}{2}-\frac {1}{10}=$$\frac{2}{5}$
$\frac {3}{5}+\frac {1}{15}=$$\frac{2}{3}$ $\frac {2}{3}-\frac {1}{2}=$$\frac{1}{6}$ $1-\frac {7}{11}=$$\frac{4}{11}$ $\frac {3}{8}+\frac {2}{5}=$$\frac{31}{40}$

答案： $\frac{5}{6}$ $\frac{1}{30}$ 1 $\frac{12}{35}$
$\frac{1}{42}$ $\frac{8}{15}$ $2\frac{1}{3}$ $\frac{11}{16}$
$\frac{5}{8}$ 1 $\frac{1}{5}$ $\frac{4}{3}$
$\frac{1}{20}$ $\frac{1}{4}$ $\frac{8}{9}$ $\frac{2}{5}$
$\frac{2}{3}$ $\frac{1}{6}$ $\frac{4}{11}$ $\frac{31}{40}$

2. 计算下面各题。(写出计算过程)(每题3★)
$\frac {4}{7}+\frac {7}{3}$ $\frac {5}{9}-\frac {2}{5}$ $\frac {3}{11}+\frac {5}{6}$

答案： $\frac{61}{21}$ $\frac{7}{45}$ $\frac{73}{66}$
（计算过程略）

3. 解方程。(每题3★)
$x-\frac {8}{15}= \frac {2}{5}$，$x=$$\frac{14}{15}$ $\frac {1}{5}+x= \frac {9}{20}$，$x=$$\frac{1}{4}$ $\frac {5}{6}-x= \frac {1}{4}$，$x=$$\frac{7}{12}$
$x+\frac {2}{5}= \frac {9}{10}$，$x=$$\frac{1}{2}$ $x-\frac {1}{4}= \frac {3}{10}$，$x=$$\frac{11}{20}$ $\frac {5}{6}+x= \frac {11}{9}$，$x=$$\frac{7}{18}$

答案： $x=\frac{14}{15}$ $x=\frac{1}{4}$ $x=\frac{7}{12}$
$x=\frac{1}{2}$ $x=\frac{11}{20}$ $x=\frac{7}{18}$