《2025年一本暑假计算加应用题五年级数学北师大版》

1. 直接写出得数。(每题 1★)
$\frac {5}{7}-\frac {2}{7}=$$\frac{3}{7}$ $\frac {2}{3}-\frac {1}{6}=$$\frac{1}{2}$ $1-\frac {3}{7}=$$\frac{4}{7}$ $1-\frac {1}{6}-\frac {5}{6}=$0
$\frac {5}{9}-\frac {1}{7}=$$\frac{26}{63}$ $\frac {5}{6}+\frac {1}{2}=$$\frac{4}{3}$ $\frac {11}{5}-\frac {5}{11}=$$\frac{96}{55}$ $\frac {6}{5}-\frac {4}{5}+\frac {1}{5}=$$\frac{3}{5}$
$\frac {14}{3}-4=$$\frac{2}{3}$ $\frac {5}{7}+\frac {2}{3}=$$\frac{29}{21}$ $0.2+\frac {1}{2}=$$\frac{7}{10}$ $\frac {3}{5}-\frac {1}{6}+\frac {1}{6}=$$\frac{3}{5}$
$2.5-\frac {4}{5}=$$\frac{17}{10}$ $\frac {8}{9}-\frac {1}{18}=$$\frac{5}{6}$ $\frac {1}{3}+\frac {1}{2}=$$\frac{5}{6}$ $\frac {1}{7}+\frac {3}{14}-\frac {1}{14}=$$\frac{2}{7}$
$\frac {3}{5}+0.4=$1 $\frac {4}{9}+\frac {8}{9}=$$\frac{4}{3}$ $\frac {3}{4}-\frac {1}{2}=$$\frac{1}{4}$ $\frac {2}{7}+\frac {5}{9}+\frac {5}{7}=$$1\frac{5}{9}$

答案： $\frac{3}{7}$ $\frac{1}{2}$ $\frac{4}{7}$ 0
$\frac{26}{63}$ $\frac{4}{3}$ $\frac{96}{55}$ $\frac{3}{5}$
$\frac{2}{3}$ $\frac{29}{21}$ $\frac{7}{10}$ $\frac{3}{5}$
$\frac{17}{10}$ $\frac{5}{6}$ $\frac{5}{6}$ $\frac{2}{7}$
1 $\frac{4}{3}$ $\frac{1}{4}$ $1\frac{5}{9}$

2. 计算下面各题,能简算的要简算。(每题 4★)
$3\frac {5}{9}-(\frac {5}{9}+\frac {7}{12})$ $3.5-(\frac {9}{10}-\frac {3}{20})$ $\frac {11}{15}+\frac {5}{7}+\frac {4}{15}-\frac {3}{7}$

答案： $2\frac{5}{12}$ 2.75 $1\frac{2}{7}$

3. 解方程。(每题 4★)
$x-\frac {5}{6}= \frac {1}{7}$，$x=$$\frac{41}{42}$ $\frac {1}{9}+x= \frac {7}{12}$，$x=$$\frac{17}{36}$ $\frac {2}{3}-x= \frac {2}{17}$，$x=$$\frac{28}{51}$
$\frac {5}{9}-x= \frac {5}{24}$，$x=$$\frac{25}{72}$ $\frac {11}{26}+x= \frac {12}{13}$，$x=$$\frac{1}{2}$ $x-\frac {1}{7}= \frac {3}{4}$，$x=$$\frac{25}{28}$

答案： $x=\frac{41}{42}$ $x=\frac{17}{36}$ $x=\frac{28}{51}$
$x=\frac{25}{72}$ $x=\frac{1}{2}$ $x=\frac{25}{28}$