《2025年一本暑假计算加应用题五年级数学北师大版》

1. 直接写出得数。(每题 1★)
$\frac {1}{8}-\frac {1}{9}=$$\frac{1}{72}$ $\frac {5}{9}-\frac {1}{3}=$$\frac{2}{9}$ $\frac {5}{8}-\frac {1}{24}=$$\frac{7}{12}$ $\frac {3}{16}+\frac {9}{16}=$$\frac{3}{4}$
$\frac {7}{10}-\frac {1}{10}=$$\frac{3}{5}$ $\frac {3}{5}+\frac {1}{8}=$$\frac{29}{40}$ $1-\frac {5}{6}=$$\frac{1}{6}$ $\frac {2}{3}+\frac {1}{6}=$$\frac{5}{6}$
$1-\frac {8}{13}=$$\frac{5}{13}$ $\frac {5}{9}-\frac {2}{9}=$$\frac{1}{3}$ $\frac {4}{5}+\frac {7}{10}=$$\frac{3}{2}$ $\frac {1}{6}+\frac {1}{4}=$$\frac{5}{12}$
$\frac {2}{7}-\frac {3}{14}=$$\frac{1}{14}$ $\frac {1}{3}+\frac {1}{24}=$$\frac{3}{8}$ $\frac {9}{5}-\frac {3}{5}=$$\frac{6}{5}$ $\frac {2}{7}-\frac {1}{14}=$$\frac{3}{14}$
$2+\frac {3}{14}=$$2\frac{3}{14}$ $\frac {3}{4}-\frac {3}{16}=$$\frac{9}{16}$ $\frac {3}{16}+\frac {5}{48}=$$\frac{7}{24}$ $\frac {7}{25}-\frac {1}{5}=$$\frac{2}{25}$

答案： $\frac{1}{72}$ $\frac{2}{9}$ $\frac{7}{12}$ $\frac{3}{4}$
$\frac{3}{5}$ $\frac{29}{40}$ $\frac{1}{6}$ $\frac{5}{6}$
$\frac{5}{13}$ $\frac{1}{3}$ $\frac{3}{2}$ $\frac{5}{12}$
$\frac{1}{14}$ $\frac{3}{8}$ $\frac{6}{5}$ $\frac{3}{14}$
2 $\frac{3}{14}$ $\frac{9}{16}$ $\frac{7}{24}$ $\frac{2}{25}$

2. 计算下面各题,能简算的要简算。(每题 3★)
$\frac {1}{5}+\frac {7}{9}-\frac {1}{5}+\frac {2}{9}$ $0.6+\frac {2}{7}+\frac {1}{3}$ $\frac {9}{10}-(\frac {3}{4}-\frac {1}{5})$
$\frac {8}{15}-(\frac {1}{2}-\frac {7}{15})$ $\frac {34}{33}-\frac {5}{7}-\frac {2}{7}$ $\frac {5}{12}+\frac {11}{15}-\frac {2}{5}+\frac {7}{12}$

答案： 1 $\frac{128}{105}$ $\frac{7}{20}$
$\frac{1}{2}$ $\frac{1}{33}$ $1\frac{1}{3}$

3. 解方程。(每题 3★)
$2x-\frac {2}{7}= \frac {5}{7}$ $x=\frac{1}{2}$ $5x-0.4= 1.1$ $x=0.3$ $3y+0.8= 2.3$ $y=0.5$

答案： $x=\frac{1}{2}$ $x=0.3$ $y=0.5$