2025年文墨小学数学口算心算天天练五年级下册人教版


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《2025年文墨小学数学口算心算天天练五年级下册人教版》

① $5 × \frac{22}{15} =$
答案: $5 × \frac{22}{15} = \frac{110}{15} = \frac{22}{3}$
② $84 × \frac{6}{7} =$
答案: $84 × \frac{6}{7} = 12 × 6 = 72$
③ $\frac{8}{9} × \frac{21}{4} =$
答案: $\frac{8}{9} × \frac{21}{4} = \frac{168}{36} = \frac{14}{3}$
④ $\frac{1}{8} - \frac{1}{9} =$
答案: $\frac{1}{8} - \frac{1}{9} = \frac{9}{72} - \frac{8}{72} = \frac{1}{72}$
⑤ $\frac{4}{45} × \frac{9}{20} =$
答案: $\frac{4}{45} × \frac{9}{20} = \frac{36}{900} = \frac{1}{25}$
⑥ $\frac{3}{7} × \frac{21}{15} × \frac{5}{8} =$
答案: $\frac{3}{7} × \frac{21}{15} = \frac{63}{105} = \frac{3}{5}$,$\frac{3}{5} × \frac{5}{8} = \frac{3}{8}$
⑦ $\frac{8}{21} - \frac{3}{10} =$
答案: $\frac{8}{21} - \frac{3}{10} = \frac{80}{210} - \frac{63}{210} = \frac{17}{210}$
⑧ $\frac{1}{4} × \frac{4}{11} =$
答案: $\frac{1}{4} × \frac{4}{11} = \frac{1}{11}$
⑨ $\frac{3}{4} + 6 =$
答案: $\frac{3}{4} + 6 = \frac{27}{4}$
⑩ $\frac{2}{5} × \frac{3}{20} =$
答案: $\frac{2}{5} × \frac{3}{20} = \frac{6}{100} = \frac{3}{50}$
⑪ $\frac{3}{8} × \frac{4}{11} =$
答案: $\frac{3}{8} × \frac{4}{11} = \frac{12}{88} = \frac{3}{22}$
⑫ $\frac{3}{8} × \frac{14}{15} =$
答案: $\frac{3}{8} × \frac{14}{15} = \frac{42}{120} = \frac{7}{20}$
⑬ $\frac{3}{20} × \frac{4}{15} =$
答案: $\frac{3}{20} × \frac{4}{15} = \frac{12}{300} = \frac{1}{25}$
⑭ $\frac{3}{11} × 55 =$
答案: $\frac{3}{11} × 55 = 3 × 5 = 15$
⑮ $\frac{6}{13} × \frac{5}{6} =$
答案: $\frac{6}{13} × \frac{5}{6} = \frac{5}{13}$
⑯ $\frac{1}{2} - \frac{1}{36} =$
答案: $\frac{1}{2} - \frac{1}{36} = \frac{18}{36} - \frac{1}{36} = \frac{17}{36}$
⑰ $\frac{1}{3} + \frac{3}{4} =$
答案: $\frac{1}{3} + \frac{3}{4} = \frac{4}{12} + \frac{9}{12} = \frac{13}{12}$
⑱ $6 × \frac{3}{27} =$
答案: $6 × \frac{3}{27} = \frac{18}{27} = \frac{2}{3}$
⑲ $\frac{3}{4} × 48 =$
答案: $\frac{3}{4} × 48 = 3 × 12 = 36$
⑳ $\frac{11}{28} × \frac{35}{11} =$
答案: $\frac{11}{28} × \frac{35}{11} = \frac{35}{28} = \frac{5}{4}$
㉑ $\frac{3}{5} × \frac{5}{8} =$
答案: $\frac{3}{5} × \frac{5}{8} = \frac{3}{8}$
㉒ $13 + \frac{5}{12} =$
答案: $13 + \frac{5}{12} = \frac{161}{12}$

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