【题目】当x=10时,求值:0.08x4–0.12x4+1.14x4=__________.


参考答案:

【答案】11 000

【解析】0.08x4–0.12x4+1.14x4=0.08–0.12+1.14x4=1.1x4,当x=10时,原式=1.1×104=11 000.故答案为:11 000.

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